Lab Report Reaction Heat Naoh Hcl
r 2.717 kJ Given the moles of water formed (0.05 mol), the enthalpy change per mole is: ΔH_neut = - (q / moles) = - (2.717 kJ / 0.05 mol) = -54.34 kJ/mol This value is close to the expected standard enthalpy change, confirming